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Which of these statements about `[Co(CN)_6]^(3-)` is true?A. `[Co(CN)_(6)]^(3-)` has four unpaired electrons and will be in a low-spin configurationB. `[Co(CN)_(6)]^(3-)` has four unpaired electrons and will be in a high-spin configurationC. `[Co(CN)_(6)]^(3-)` has no unpaired electrons and will be in a high - spin configurationD. `[Co(CN)_(6)]^(3-)` has no unpaired electron and will be in a low-spin configuration |
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Answer» Correct Answer - D `[Co(CN)_(6)]^(-3)` O.N. of Co`=+3` `Co^(+3) = 4s^(0) 3d^(6)`, `CN^(-)` is strong field ligand so hybridisation is `d^(2)sp^(3)` and has no unpaired electrons. |
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