Which one is wrong if electrolysis of `CH_(3)COONa(aq)` is made using `Pt` electrodes ?A. `pH` of solution increases.B. Molar ratio of gases at anode and cathode is `3:1`C. `[CH_(3)COO^(c-)]` in solution decreases.D. The molar ration of gases at anode and cathode is `2:1`

Which one is wrong if electrolysis of `CH_(3)COONa(aq)` is made using

1.	Which one is wrong if electrolysis of `CH_(3)COONa(aq)` is made using `Pt` electrodes ?A. `pH` of solution increases.B. Molar ratio of gases at anode and cathode is `3:1`C. `[CH_(3)COO^(c-)]` in solution decreases.D. The molar ration of gases at anode and cathode is `2:1`
Answer» Correct Answer - d Anode`:2CH_(3)COO^(c-)rarr C_(2)H_(6)+2CH_(2)+2e^(-)` Cathode `:2H^(o+)+2e^(-) rarr H_(2)` `(CO_(2):H_(2)=2:1)`

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Define molar conductivity of a solution and explain how molar conductivity changes with change in concentration of a solution for a weak and a strong electrolyte.
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Limiting molar conductivity of `NH_(4)OH` [i.e., `Lambda_(m)^(@)(NH_(4)OH)`] is equal to:A. `Lambda_(m)^(@)(NH_(4)Cl)+Lambda_(m)^(@)(Na_(4)Cl)-Lambda_(m)^(@)(NaOH)`B. `Lambda_(m)^(@)(NaOH)+Lambda_(m)^(@)(NaCl)-Lambda_(m)^(@)(NH_(4)Cl)`C. `Lambda_(m)^(@)(NH_(4)OH)+Lambda_(m)^(@)(NH_(4)Cl)-Lambda_(m)^(@)(HCl)`D. `Lambda_(m)^(@)(NH_(4)Cl)+Lambda_(m)^(@)(NaOH)-Lambda_(m)^(@)(NaCl)`
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Based on the data given below, the correct order of reducing power is: `Fe_((aq.))^(3+) + e rarr Fe_((aq.))^(2+), E^(@) = +0.77 V` `Al_((aq.))^(3+) + 3e rarr Al_((s)), E^(@) = -1.66 V` `Br_(2(aq.)) + 2e rarr 2Br_((aq.))^(-), E^(@) = +1.08 V`A. `Br^(-) lt Fe^(2+) lt A1`B. `Fe^(2+) lt Al lt Br^(-)`C. `Al^(-) lt Br^(-) lt Fe^(2+)`D. `Al^(-) lt Fe^(2+) lt Br^(-)`
Based on the data given below, the correcy order of reducing power is: `Fe_((aq.))^(3+) + e rarr Fe_((aq.))^(2+), E^(@) = +0.77 V` `Al_((aq.))^(3+) + 3e rarr Al_((s)), E^(@) = -1.66 V` `Br_(2(aq.)) + 2e rarr 2Br_((aq.))^(-), E^(@) = +1.08 V`A. `Br^(-) lt Fe^(2+) lt Al`B. `Fe^(2+) lt Al lt Br^(-)`C. `Al lt Br^(-) lt Fe^(2+)`D. `Al lt Fe^(2+) lt Br^(-)`
Based on the data given below, the correcy order of reducing power is: `Fe_((aq.))^(3+) + e rarr Fe_((aq.))^(2+), E^(@) = +0.77 V` `Al_((aq.))^(3+) + 3e rarr Al_((s)), E^(@) = -1.66 V` `Br_(2(aq.)) + 2e rarr 2Br_((aq.))^(-), E^(@) = +1.08 V`A. `Br^(-) lt Fe^(2+) lt Al`B. `Fe^(2+) lt Al lt Br^-`C. `Al lt Br^(-) lt Fe^(2+)`D. `Al lt Fe^(2+) lt Br^(-)`
What are elementary reactions ?

Which one is wrong if electrolysis of `CH_(3)COONa(aq)` is made using `Pt` electrodes ?A. `pH` of solution increases.B. Molar ratio of gases at anode and cathode is `3:1`C. `[CH_(3)COO^(c-)]` in solution decreases.D. The molar ration of gases at anode and cathode is `2:1`

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