Which one of the following arrangements does not give the correct picture of the trends indicated against it ? (i) F_(2) gt Cl_(2) gt Br_(2) gt l_(2) : Oxidizing power (ii) F_(2) gt Cl_(2) gt Br_(2) gt l_(2) : Electron gain enthalpy (iii) F_(2) gt Cl_(2) gt Br_(2) gt l_(2) : Bond dissociation energy (iv) F_(2) gt Cl_(2) gt Br_(2) gt l_(2) : Electronegativity.

Which one of the following arrangements does not give the correct pict

1.	Which one of the following arrangements does not give the correct picture of the trends indicated against it ? (i) F_(2) gt Cl_(2) gt Br_(2) gt l_(2) : Oxidizing power (ii) F_(2) gt Cl_(2) gt Br_(2) gt l_(2) : Electron gain enthalpy (iii) F_(2) gt Cl_(2) gt Br_(2) gt l_(2) : Bond dissociation energy (iv) F_(2) gt Cl_(2) gt Br_(2) gt l_(2) : Electronegativity.
Answer» II and iv I and iii ii and iii ii, iii and iv Solution :From the given options we find option (i) is correct. The oxidising POWER of halogens follow the order `F_(2) gt Cl_(2) gt Br_(2) gt I_(2)`. Option (ii) is incorrect because it in not the correct order of electron gain enthalpy of halogens. The correct order is `Cl_(2) gt F_(2) gt Br_(2) gt I_(2)` . The low value of `F_(2)` than `Cl_(2)` is DUE to its small size. Option (iii) is incorrect. The correct order of bond dissociation energies of halogens is `Cl_(2) gt Br_(2) gt F_(2) gt I_(2)` Option (iv) is correct. It is the correct order of ELECTRONEGATIVITY VALUES of halogens. Thus option (ii) and (iii) are incorrect.