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Which one of the following has highest bond order ? N_(2) , N_(2)^(+) " or " N_(2)^(-) |
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Answer» SOLUTION :`N_(2) ` (14 electrons) BOND order = 3 Bond order ` = (N_(b)- N_(a))/2 = (10 - 4)/2 = 3` `N_(2)^(+)` ( 13 electrons) Bond order= `2.5` Bond order ` = (N_(b) - N_(a))/2 = (9-4)/ 2 = 2.5` `N_(2)^(-) ` ( 15 electrons) Bond order ` = 2.5` Bond order ` = (N_(b) - N_(a))/2 = (10 - 5)/2 = 2.5`. So , `N_(2)` has the highest bond order . |
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