Saved Bookmarks
| 1. |
Which one of the following has highest bond order? N_(2), N_(2)^(+) or N_(2)^(-)? |
|
Answer» Solution :`N_(2)` (14 electrons) Bond ORDER = 3, B.O. = `(N_(b)-N_(a))/(2)=(10-4)/(2)=3` `N_(2)^(+)` (13 electrons) Bond order = 2.5, B.O. `=(N_(b)-N_(a))/(2)=(9 - 4)/(2)=2.5` `N_(2)^(-)` (15 electrons) Bond order `= 2.5, B.O. = (N_(b)-N_(a))/(2)=(10 -5)/(2)=2.5` So `N_(2)` has the HIGHEST bond order. |
|