1.

Which one of the following ions is the most stable in aqueous solutions ? (At. No. `Ti=22, V=23, Cr= 24 , Mn = 25)A. `Mn^(2+)`B. ` Cr^(3+)`C. `V^(3+)`D. `Ti^(3+)`

Answer» Out of the given species, `Cr^(3+)` has the highest negative reduction potential.Hence, it cannot be reduced to `Cr^(2+)` and, therefore, is the most stable ion in aqueous solution.
Alternatively,
`Mn^(3+) = [ AAr] 3d^(4) , Cr^(3+)= [Ar]3d^(3)`
`V^(3+) =[Ar]3d^(2)Ti ^(3+) = [ Ar] 3d^(1)`
In `Cr^(3+)`, all three d electrons enter into lower energy `t_(2g)` orbitals. The lowering of energy is maximum and hence stability is maximum.


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