1.

Which one of the following pairs of species have the same bond order ?

Answer»

`NO^(+) and CN^(+)`
`CN^(-) and NO^(+)`
`CN^(-) and CN^(+)`
`O_(2)^(-) and CN^(-)`

Solution :`CN^(-) and NO^(+)`
In the given pair of species
NUMBER of electron in `NO^(+)` = number of electron in `CN^(-)` = 14 electrons.
So they are isoelectronic in nature.
HENCE bond order of these two species will be also si.milar which is shown below.
`N^(+) rarr sigma 1S^(2) sigma^(**) 1s^(2) sigma 2s^(2) sigma^(**) 2s^(2) sigma 2p_(z)^(2) pi 2p_(x)^(2) pi 2p_(y)^(2)`
B.O =1/2 `[N_(b) - N_(a)] `
= 1/2 [ 10 - 4]
or B.O = 3
`CN^(-) rarr sigma 1s^(2) sigma^(**) 1s^(2) sigma 2s^(2) sigma^(**) 2s^(2) pi 2p_(x)^(2) pi 2p_(y)^(2) sigma 2p_(z)^(2)`
B.O = 1/2 [ 10 - 4] or B.O = 3


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