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Which one of the following pairs of species have the same bond order ? |
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Answer» `NO^(+) and CN^(+)` In the given pair of species NUMBER of electron in `NO^(+)` = number of electron in `CN^(-)` = 14 electrons. So they are isoelectronic in nature. HENCE bond order of these two species will be also si.milar which is shown below. `N^(+) rarr sigma 1S^(2) sigma^(**) 1s^(2) sigma 2s^(2) sigma^(**) 2s^(2) sigma 2p_(z)^(2) pi 2p_(x)^(2) pi 2p_(y)^(2)` B.O =1/2 `[N_(b) - N_(a)] ` = 1/2 [ 10 - 4] or B.O = 3 `CN^(-) rarr sigma 1s^(2) sigma^(**) 1s^(2) sigma 2s^(2) sigma^(**) 2s^(2) pi 2p_(x)^(2) pi 2p_(y)^(2) sigma 2p_(z)^(2)` B.O = 1/2 [ 10 - 4] or B.O = 3 |
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