1.

Which one of the following transition metal ions shows magnetic moment of 5.92 BM?

Answer»

`Mn^(2+)`
`Ti^(3+)`
`Cr^(3+)`
`Cu^(2+)`

Solution :Given magnetic MOMENT of transition METAL
`=sqrt(n(n+2))=5.92`
i.e., n=5
Number of unpaired electrons in `Mn^(2+)=5`
Number of unpaired electrons in `Ti^(3+)=1`
Number of unpaired electrons in `Cr^(3+)=3`
Number of unpaired electrons in `Cu^(2+)=1`
Number of unpaired electrons in `CO^(2+)=3`
THUS `Mn^(2+)` have magnetic moment`=5.92BM`


Discussion

No Comment Found

Related InterviewSolutions