Which one of the following will have largest number of atoms?(i) 1 g of Au (s) (ii) 1 g of Na (s) (iii) 1 g of Li (s) (iv)1g Cl_(2) (g)

Which one of the following will have largest number of atoms?(i) 1 g o

1.	Which one of the following will have largest number of atoms?(i) 1 g of Au (s) (ii) 1 g of Na (s) (iii) 1 g of Li (s) (iv)1g Cl_(2) (g)
Answer» Solution :(i) Molar mass of Au = 197 g `mol^(-1)` No. of atoms in 1 g of Au = `1/197 XX 6.023 xx 10^(23)` (II) Molar mass of NA = 23 g `mol^(-1)` No. of atoms in 1 g of Na = `1/23 xx 6.023 xx 10^(23)` (iii) Molar mass of Li = 7 g `mol^(-1)` No. of atoms in 1 g of Li =` 1/7 xx 6.023 X 10^(23)` (iv) Molar mass of CL, = 71 g `mol^(-1)` No. of atoms in 1 g of `Cl_(2)= 1/71 xx 6.023 x 10^(23)` Comparing the number of atoms, the LARGEST number of atoms will be present in 1 g of Li. Since the mass is same in each case, the element with the lowest molar mass would have the largest number of atoms. `:.` Li with lowest molar mass would have the largest number of atoms.