Which one of the following will have largest number of atoms ? (i) 1 g Au_((s)) (ii) 1g Na_((s)) (iii) 1 g Li_((s)) (iv) 1 g Cl_(2(g))

Which one of the following will have largest number of atoms ? (i) 1

1.	Which one of the following will have largest number of atoms ? (i) 1 g Au_((s)) (ii) 1g Na_((s)) (iii) 1 g Li_((s)) (iv) 1 g Cl_(2(g))
Answer» Solution :(i) 1 gm `Au = (1)/(197) ` MOL Au MOLECULE `=(1)/(197)xx6.022xx10^(23)` Au atom (ii) 1 gm `Na=(1)/(23)` mol Na molecule `=(1)/(23) xx 6.022 xx 10^(23)` Na atom (iii) 1 gm `Li=(1)/(7)` mol Li molecule `= 1/7 xx 6.022 xx 10^(23)` Li atom (IV) 1 gm `Cl_(2) = (1)/(71) mol Cl_(2)` molecule `=(1)/(71) xx 6.022 xx 10^(23)` `=(2)/(71) xx 6.022 xx 10^(23) Cl_(2)` atom