1.

Which one of the following will have largest number of atoms ? (i) 1 g Au(s) (ii) 1 g Na (s) (iii) 1 g Li (s) (iv) 1 g of Cl_(2)(g) (Atomic masses : Au = 197, Na = 23, Li = 7, Cl = 35.5 amu)

Answer»

Solution :(i) `"1 G Au"=(1)/(197)" MOL "=(1)/(197)xx6.02xx10^(23)" atosm"`
(ii)`"1 g Na"=(1)/(23)" mol "=(1)/(23)xx6.02xx10^(23)" atosm"`
(III) `"1 g LI"=(1)/(7)" mol "=(1)/(7)xx6.02xx10^(23)" atosm"`
(iv)`"1 g Cl"_(2)=(1)/(71)" mol "=(1)/(71)xx6.02xx10^(23)" molecules"=(2)/(71)xx6.02xx10^(23)" atoms"`


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