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Which one of the following will have largest number of atoms? a. `1 g Au(s)` b. `1g Na_(4)(s)` c. `1 g Li(s)` d. `1 g Cl_(2)(g)` |
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Answer» a. `1 g Au=1/197 mol=1/197xx6.02xx10^(23)` atoms b. `1 g Na=1/23 mol=1/23xx6.02xx10^(23)` atoms c. `1g Li=1/7 mol =1/7xx6.02xx10^(23)` atoms d. `1 g Cl_(2)=1/71 mol =1/71xx6.02xx10^(23)` molecules `=2/71xx6.02xx10^(23)` atoms Thus, `1 g` of `Li` has the largest number of atoms. |
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