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Which one of the following will have largest number of atoms?(i) 1 g Au (s)(ii) 1 g Na (s)(iii) 1 g Li (s)(iv) 1 g of Cl2 (g) |
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Answer» (i) Number of atoms in 1 g of Au = {197}/{6.022 x 1023} = 32.7 x 10-23 (ii) Number of atoms in 1 g Na = {2.3}/{6.022 x 1023} = 3.82 x 10-23 (iii) Number of atoms in 1 g of Li = {7}/{6.022 x 1023} = 1.16 x 10-23 (iv) Number of atoms in 1 g Cl2 = {35.5}/{6.022 x 1023} = 5.89 x 10-23 1 g gold will have the largest number of atoms. |
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