Which one of the following will have the largest number of atoms? (i) 1 g Au (s) (ii) 1 g Na (s) (iii) 1 g Li (s) (iv) 1 g of Cl2(g)

Which one of the following will have the largest number of atoms? (i)

1.	Which one of the following will have the largest number of atoms? (i) 1 g Au (s) (ii) 1 g Na (s) (iii) 1 g Li (s) (iv) 1 g of Cl2(g)
Answer» Solution :(i) `1g AU = 1/197 "mole" = 1/197 xx 6.022 xx 10^(23) = 3.057 xx 10^(21)` atoms (II) `1 G Na = 1/23 "mole" =1/23 xx 6.022 xx 10^(23) = 2.618 xx 10^(22)` atoms (iii) `1g of Li =1/7 "mole" =1/7 xx 6.022 xx 10^(23) = 8.0603 xx 10^(22)` atoms (iv) `1g Cl_(2) = 1/71 "mole" =1/71 xx 6.022 xx 10^(23)` MOLECULES = `1/71 xx 6.022 xx 10^(23) xx 2` atoms `=1.696 xx 10^(22)` atoms. Hence, 1 g Li will contain the largest number of atoms.