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Which one of the folowing has highest bond order? N_(2),N_(2)^(+)orN_(2)^(-) ? |
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Answer» Solution :Bond ORDER=`3,B.O=(N_(b)-N_(a))/(2)=(10-4)/(2)=3` `N_(2)^(+)` (13 electrons) Bond order=`2.5,B.O=(N_(b)-N_(a))/(2)=(9-4)/(2)=2.5` `N_(2)^(-)` (15 electrons) Bond order=`2.5,B.O=(N_(b)-N_(a))/(2)=(10-5)/(2)=2.5` So`N_(2)` has the HIGHEST bond order. |
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