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Which orbitals on overlapping will form sigma and pi-bond in C=C of alkene ? Explain. |
Answer» Solution :For the FORMATION of `SIGMA`-bond the `sp^(2)-sp^(2)` ORBITALS are overlap on the same edges on two carbon atoms.  Every carbon atoms has three `sp^(2)` orbital where two other atoms are attached and with other carbon atoms from `sigma`-bonds. Two unhybridized 2p orbitals of two carbon perpendicular to planner overlap with each other and forms `PI`-bond. 
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