1.

Which pair of electrolytes could not be distinguished by the products of electrolysis using inert electrodes?

Answer»

1 M `CuSO_(4)` solution, 1 M `CuCl_(2)` solution
1 M KCl solution, 1 M KI solution
1 M `AgNO_(3)` solution, 1 M `Cu(NO_(3))_(2)` solution
1 M KCl solution, 1 M NaCl solution

Solution :(a) `CuSO_(4)toCu+O_(2),CuCl_(2)toCu+Cl_(2)`
(b) `KCl toH_(2)+Cl_(2),KItoH_(2)+I_(2)`
(C) `AgNO_(3)toAg+O_(2),Cu(NO_(3))_(2)toCu+O_(2)`
(d) `KCl to H_(2)+Cl_(2),NaCl toH_(2)+Cl_(2)`
(E) `CuBrtoCu+Br_(2),CuSO_(4)toCu+O_(2)`
Thus, KCl and NaCl solutions give the same products at anode and cathode.


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