1.

Which pair of electrolytes could not be distinguished by the products of electrolysis using inert electrodes.

Answer»

1M `CuSO_(4)` solution, `1M CuCl_(2)` solution
1M KCl solution, 1M KI solution
1 M `AgNO_(3)` solution `1M Cu(NO_(3))` solution
1M `CuBr_(2)` solution `1M CuSO_(4)` solution.

Solution :(A) `CuSO_(4)rarrCu+O_(2):CuCl_(2)rarrCu+I_(2)`
(B) `KClrarrH_(2)+Cl_(2):KIrarrH_(2)+I_(2)`
(C) `AgNO_(3)rarrAG+O_(2),:NaClrarrH_(2)+Cl_(2)`
(D) `KClrarrH_(2)+Cl_(2):NaClrarrH_(2)+Cl_(2)`
(E) `CuBrrarrCu+Br_(2):CuSO_(4)rarrCu+O_(2)`
Thus KCl and NaCl solution give the same products at ANODE and CATHODE.


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