Which pair of electrolytes could not be distinguished by the products of electrolysis using inert electrodes.A. 1M `CuSO_(4)` solution, `1M CuCl_(2)` solutionB. 1M KCl solution, 1M KI solutionC. 1 M `AgNO_(3)` solution `1M Cu(NO_(3))` solutionD. 1M `CuBr_(2)` solution `1M CuSO_(4)` solution.

Which pair of electrolytes could not be distinguished by the products

1.	Which pair of electrolytes could not be distinguished by the products of electrolysis using inert electrodes.A. 1M `CuSO_(4)` solution, `1M CuCl_(2)` solutionB. 1M KCl solution, 1M KI solutionC. 1 M `AgNO_(3)` solution `1M Cu(NO_(3))` solutionD. 1M `CuBr_(2)` solution `1M CuSO_(4)` solution.
Answer» Correct Answer - A (A) `CuSO_(4)rarrCu+O_(2):CuCl_(2)rarrCu+I_(2)` (B) `KClrarrH_(2)+Cl_(2):KIrarrH_(2)+I_(2)` (C) `AgNO_(3)rarrAG+O_(2),:NaClrarrH_(2)+Cl_(2)` (D) `KClrarrH_(2)+Cl_(2):NaClrarrH_(2)+Cl_(2)` (E) `CuBrrarrCu+Br_(2):CuSO_(4)rarrCu+O_(2)` Thus KCl and NaCl solution give the same products at anode and cathode.

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Which pair of electrolytes could not be distinguished by the products of electrolysis using inert electrodes.A. 1M `CuSO_(4)` solution, `1M CuCl_(2)` solutionB. 1M KCl solution, 1M KI solutionC. 1 M `AgNO_(3)` solution `1M Cu(NO_(3))` solutionD. 1M `CuBr_(2)` solution `1M CuSO_(4)` solution.

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