Which pair of electrolytes could not be distinguished by the products of electrolysis using inert electrodes?A. 1 M `CuSO_(4)` solution, 1 M `CuCl_(2)` solutionB. 1 M KCl solution, 1 M KI solutionC. 1 M `AgNO_(3)` solution, 1 M `Cu(NO_(3))_(2)` solutionD. 1 M KCl solution, 1 M NaCl solution

Which pair of electrolytes could not be distinguished by the products

1.	Which pair of electrolytes could not be distinguished by the products of electrolysis using inert electrodes?A. 1 M `CuSO_(4)` solution, 1 M `CuCl_(2)` solutionB. 1 M KCl solution, 1 M KI solutionC. 1 M `AgNO_(3)` solution, 1 M `Cu(NO_(3))_(2)` solutionD. 1 M KCl solution, 1 M NaCl solution
Answer» Correct Answer - D (a) `CuSO_(4)toCu+O_(2),CuCl_(2)toCu+Cl_(2)` (b) `KCl toH_(2)+Cl_(2),KItoH_(2)+I_(2)` (c) `AgNO_(3)toAg+O_(2),Cu(NO_(3))_(2)toCu+O_(2)` (d) `KCl to H_(2)+Cl_(2),NaCl toH_(2)+Cl_(2)` (e) `CuBrtoCu+Br_(2),CuSO_(4)toCu+O_(2)` Thus, KCl and NaCl solutions give the same products at anode and cathode.

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Which pair of electrolytes could not be distinguished by the products of electrolysis using inert electrodes?A. 1 M `CuSO_(4)` solution, 1 M `CuCl_(2)` solutionB. 1 M KCl solution, 1 M KI solutionC. 1 M `AgNO_(3)` solution, 1 M `Cu(NO_(3))_(2)` solutionD. 1 M KCl solution, 1 M NaCl solution

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