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Which Q_(sp) will be high from 0.0001 M BaCrO_4 and 0.0001 M Ag_2CrO_4 ? |
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Answer» SOLUTION :`Q_(sp) (BaCrO_4)=(0.0001)^2=1xx10^(-8)` `Q_(sp)(Ag_2CrO_4)=4S^3=4(0.0001)^3=4xx10^(-12)` THEREFORE `Q_(sp)` of `BaCrO_4` is less. |
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