Which quantity out of Delta_(r)G " and " Delta_(r) G^(Θ) will be zero at equilibrium ?

Which quantity out of Delta_(r)G " and " Delta_(r) G^(Θ) will be zero

1.	Which quantity out of Delta_(r)G " and " Delta_(r) G^(Θ) will be zero at equilibrium ?
Answer» Solution :Gibbs ENERGY for a REACTION in which all reactants and products are in standard STATE. `Delta_(r)G^(Θ)` is related to the equilibrium constant of the reaction as follows `Delta_(r)G = Delta_(r)G^(Θ) + RT LN K` At equilibrium, `0 = Delta_(r) G^(@) + RT ln K "" ( :. Delta_(r) G = 0)` or `Delta_(r) G^(Θ) = - RT ln K` `Delta_(r) G^(Θ) = 0` When `K = 1` For all other values of `K, Delta_(r)G^(Θ)` will be non-zero.