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Which quantity out of Delta_(r) G and Delta_(r) G^( Theta ) will be zero at equilibrium ? |
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Answer» Solution :Gibbs energy for a REACTION in which all reactants and products are in standard state. `Delta_(r) G^( THETA )` is related to the EQUILIBRIUM constant of the reaction as FOLLOWS : `Delta_(r) G= Delta_(r) G^( Theta ) + "RT In K"` At equilibrium, `0= Delta_(r) G^( Theta ) + "RT In k" (because Delta_(r) G= 0)` OR `Delta_(r) G^( Theta ) =- "RT In k"` `Delta_(r) G^( Theta ) = 0 "when" K=1` For all other values of `K, Delta_(r) G^( Theta )` will be non-zero. |
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