1.

Which reagent cannot be used to prepare haloakane from an alcohol?

Answer»

HCl<BR>HBr
HI
`Br_(2)`

Solution :With `HX(X=Cl,Br,I)` the reaction occurs via protonation. The protonated ALCOHOL then react with `X^(-)` to fromhaloalkane. An alcohol does not react with `Br_(2)`because there is a no protonating agne and secondly, the extermely WEAK base `Br^(-)` cannot displace very STRONG base `OH^(-)`


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