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Which shows one way to determine the factors of x3 - 12x2 - 2x + 24 by grouping? x(x2 - 12) + 2(x2 - 12) x(x2 - 12) - 2(x2 - 12) x2(x - 12) + 2(x - 12) x2(x - 12) - 2(x - 12) |
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Answer» Which shows one way to determine the factors of x3 - 12x2 - 2x + 24 by grouping? x(x2 - 12) + 2(x2 - 12) x(x2 - 12) - 2(x2 - 12) x2(x - 12) + 2(x - 12) x2(x - 12) - 2(x - 12) Solution: |
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