Which smallest number should be subtracted from 1936 that whdivided by

1.	Which smallest number should be subtracted from 1936 that whdivided by 9, 10 and 15, leaves 7 as remainder in each case.iVI
Answer» The answer for this question is39. Explanation : Step 1-Take LCM (9,10,15) = 90 Step 2 - Divide 1936 by 90. 1936÷90 = 21 (quotient) and 46(remainder) Step 3 - To get 7 as remainder you must subtract 39. As 46–39 = 7 Result :1936–39 = 1897 1897÷9 = 210(quotient) + 7(remainder) 1897÷10 = 189(quotient) + 7(remainder) 1897÷15 = 126(quotient) + 7(remainder

Which smallest number should be subtracted from 1936 that whdivided by 9, 10 and 15, leaves 7 as remainder in each case.iVI

Answer»

The answer for this question is39.

Explanation :

Step 1-Take LCM (9,10,15) = 90

Step 2 - Divide 1936 by 90.

1936÷90 = 21 (quotient) and 46(remainder)

Step 3 - To get 7 as remainder you must subtract 39.

As 46–39 = 7

Result :1936–39 = 1897

1897÷9 = 210(quotient) + 7(remainder)

1897÷10 = 189(quotient) + 7(remainder)

1897÷15 = 126(quotient) + 7(remainder