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Which state of triply ionized beryliium (Be^(3+)) has the same orbital radius as that of the grounnd state of hydrogen atom ? |
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Answer» Solution :For H-like particles, `r_(n) = 0529 XX (n^(2))/(Z)` For ground state of H-atom, `Z = 1, n = 1, r_(1) = 0.529 Å` For `Be^(3+) (Z = 4)`, if nth orbit has the same radius, then `0.529 xx (n^(2))/(4) = 0.529 or n^(2) = 4 " i.e., " n = 2` THUS, second orbit of `Be^(3+)` ion has same radius as that of ground state (1ST orbit) of H-atoms |
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