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Which statement is incorrect?A. `[Ni(CO)_(4)]` - tretrahedral, paramagneticB. `[Ni(CN)_(4)]^(2-)` - square planar, diamagneticC. `[Ni(CO)_(4)]` - tetrahedral, diamagneticD. `[Ni(CI)_(4)]^(2-)` - tetrahedral, paramagnetic

Answer» Correct Answer - A
In `[Ni(CO)_(4)]` , the oxidation number of Ni is zero. `Ni^(0) (3d^(8) 4s^(2))` Since CO is a strong field ligand, the electron configuration is resuffled so as to make 4s orbital empty for `sp^(3)` hybrization. All the electrons arer paired and the complex is tetrahedral.


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