1.

Which statements are correct for the peroxide ion-

Answer»

it has five completely filled anti-bonding molecular orbitals
it is DIAMAGNETIC
it has bond order one
It is isoelectronic with neon

Solution :MO electronic configuration of `O_(2)^(2-)` (peroxide ion):
`(sigma_(1s))^(2)(sigma_(1s)^(**))^(2)(sigma_(2s))^(2)(sigma_(2s)^(**))^(2)(sigma_(2p_(z)))^(2)`
`(pi_(2px))^(2)(pi_(2py))^(2)(pi_(2p_(x))^(**))^(2)(pi_(2p_(y))^(**))^(2)`
bond order`=(N_(b)-N_(a))/(2)=(10-8)/(2)=1`
THUS, there is no unpared electron present for which it becomes diamagnetic. its total no. of electrons=18 (same as that of Ne).


Discussion

No Comment Found