1.

Which term in the expansion of (2-3x)^(19) has algebrically the last coefficients ?

Answer»

`10^(th)`
`11^(th)`
`12^(th)`
`13^(th)`

Solution :For algebraically the LEAST coefficient we first FIND the numerically the greatest term for `x = 1`.
Using `r le (n+1)/(1+|(a)/(bx)|)`, we get
`RLE(19+1)/(1+|2/3|)rArr r le 12`
Therefore, `T_(13)` and `T_(12)` have numerically the greatest conefficient.
`T_(12)` is ALGEBRICALLY the least as it is followedby negative sign.


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