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Which term in the expansion of `(2-3x)^(19)` has algebrically the last coefficients ?A. `10^(th)`B. `11^(th)`C. `12^(th)`D. `13^(th)`

Answer» Correct Answer - C
For algebraically the least coefficient we first find the numerically the greatest term for `x = 1`.
Using `r le (n+1)/(1+|(a)/(bx)|)`, we get
`rle(19+1)/(1+|2/3|)rArr r le 12`
Therefore, `T_(13)` and `T_(12)` have numerically the greatest conefficient.
`T_(12)` is algebrically the least as it is followed by negative sign.


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