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Which term in the expansion of `(2-3x)^(19)` has algebrically the last coefficients ?A. `10^(th)`B. `11^(th)`C. `12^(th)`D. `13^(th)` |
Answer» Correct Answer - C For algebraically the least coefficient we first find the numerically the greatest term for `x = 1`. Using `r le (n+1)/(1+|(a)/(bx)|)`, we get `rle(19+1)/(1+|2/3|)rArr r le 12` Therefore, `T_(13)` and `T_(12)` have numerically the greatest conefficient. `T_(12)` is algebrically the least as it is followed by negative sign. |
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