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Which will not give precipitate with `NH_(4)OH` Solution ?A. `FeCl_(3)`(aq)B. `Al_(2)(SO_(4))_(3)`(aq)C. `CuSO_(4)`(aq)D. `CrCl_(3)`(aq) |
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Answer» Correct Answer - C `CuSO_(4)` (aq) form a soluble complex with `NH_(4)OH` `CuSO_(4)+4NH_(4)OH` to `underset("Soluble")([Cu(NH_(3))_(4)])SO_(4)+4H_(2)O` |
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