1.

While charging lead storage battery

Answer»

`PbSO_4` on cathodc is reduced to Pb
`PbSO_4` on ANODE is oxidised to `PbO_2`
`PbSO_4` on anode is reduced to Pb
`PbSO_4` on cathode is oxidised to Pb

SOLUTION :CHARGING : anode : `PbSO_(4)(s) + 2e^(-) to Pb(s) + SO_4^(2-) (aq)`
Cathode : `PbSO_4(s) + 2H_2O(l) to PbO_2(s) + SO_4^(2-) (aq) + 2e^(-)` .


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