1.

While charging the leadstorage battery

Answer»

`PbSO_(4)` on cathode is reduced to Pb
`PbSO_(4)` on ANODE is oxidized to `PbO_(2)`
`PbSO_(4)` on anode is reduced to Pb
`PbSO_(4)` on cathodeis oxidized to Pb

Solution :REACTIONS occuring during charging are :
`{:("Anode :"PbSO_(4(s))+2e^(-)RARR Pb_((s))+SO_(4(AQ))^(2-)),("Cathode : "PbSO_(4(s))+2H_(2)OrarrPbO_(2(s))+SO_(4(aq))^(2-)+4H_((aq))^(+)+2e^(-)),(ulbar(2PbSO_(4(s))+2H_(2)OrarrPb_((s))+PbO_(2(s))+2H_(2)SO_(4(aq))"")):}`


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