1.

While launching a rocket of mass 2xx10^(4) kg, a force of 5xx10^(5)N is applied for 20s. What is the velocity attained by the rocket at the end of 20s?

Answer»

300m/s
350 m/s
450 m/s
500 m/s

Solution :Impulse = Change in momentum
`therefore F XX t= m(V-u), " where " u=0`
`5XX10^(5) xx 20 = 2XX10^(4) xx v`
`thereforev= (100xx10^(5))/(2xx10^(4))= 500m//s`


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