InterviewSolution
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InterviewSolution
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While measuring acceleration due to gravity by simpe pendulum a student makes a positive error of 1% in the length of the pendulum and a negative error of 3% in the value of the time period. His percentage error in the measurement of the value of g will be -A. `2%`B. `4%`C. `7%`D. `10%` |
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Answer» Correct Answer - C `T= 2pi sqrt((l)/(g)) rArr g = (4pi^(2) l)/( T^(2))` `(Delta g)/(g) xx 100 = (Delta l)/(l ) xx 100 + (2 Delta T)/(T) xx 100` `" "= 1 % + 2(3 % ) = 7%` |
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