1.

Why a force is applied at right angles to the heavy door at the outer edge while closing or opening it?

Answer»

Solution :TORQUE `tau=F R SIN theta`
For a force applied at right ANGLE to the OUTER edge of the door i.e. `theta=90^(@) :' sin 90^(@)=1`
`:. tau=Fr`
`:.` The values of `sin theta` and r are maximum.
So, torque produced is maximum. Hence force is applied at right angles to the heavy door at the outer edge.


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