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Why a force is applied at right angles to the heavy door at the outer edge while closing or opening it? |
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Answer» Solution :TORQUE `tau=F R SIN theta` For a force applied at right ANGLE to the OUTER edge of the door i.e. `theta=90^(@) :' sin 90^(@)=1` `:. tau=Fr` `:.` The values of `sin theta` and r are maximum. So, torque produced is maximum. Hence force is applied at right angles to the heavy door at the outer edge. |
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