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Why are circular roads banked? Deduce an expression for maximum speed of a vehicle which can be achieved while taking a turn on the banked curved road neglecting friction. |
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Answer» Solution :The breadths of circular roads are sometimes kept slanted with the horizontal. This is called banking. In a banked road, the normal reaction of a vehicle would have a horizontal component. This contributes to the centripetal FORCE of circular motion, and thus helps a vehicle to have a greater safe speed. In `theta` = banking angle, N = normal reaction, Ncos `theta` = vertical component of N, which balances the weight mg of the vehicle, Nsin`theta` = horizontal component of N, which supplies the centripetal force `(mv^(2))/(R )` for the vehicle moving with velocity v in a path of radius r. `therefore "" " Ncos"theta = " mg" "" and " Nsin " theta = (mv^(2))/(r )` Then, `("Nsin"theta)/("Ncos"theta) = ((mv^(2))//r)/(mg) ` or,tan`theta = (v^(2))/(rg) ""or, v = sqrt("rgtan"theta)` this is the maximum velocity that a vehicle may achieve in the curved path. In this treatment, we neglected the effect of friction [ However, friction plays a very important role in motions ALONG curved paths. for example, if the road is not banked , `theta` = 0 , then our formula gives v = 0 . But in practice, vehicles can turn in curved paths even in the absence of banking . in that case, the entire centripetal force is provided by friction] .
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