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Why are `Mn^(2+)` compounds more stable than `Fe^(2+)` comounds towards oxidation to their `+3` state ?

Answer» Electronic configuration of `Mn^(2+)` is `3d^(5)` which is half filled and hence stable. Therefore, 3rd ionizatio enthalpy is very high, i.e., 3rd electron cannot be lost easily. In case of `Fe^(2+)` , electronic configuration is `3d^(6)` . Hence, it can lose one electron easily to give the stable configuration `3d^(5)`


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