InterviewSolution
Saved Bookmarks
| 1. |
Why are (o + p) in ratious for the SE reaction (e.g. nitraction) of toluene and PhCF, 32.3 and 0.14, respectively ? |
|
Answer» Solution :In TOULENE, `(-CH_(3))` group is the activating group (due to three `H.C`. Sturctures). Also, it is `sigma-` and `p` directing so `(( o + p))/(m)` ratio is very high. In PhCF_(3), (-CF_(3))` is the decavating group to `-1` effect of three `F` atoms on the `ALKYL C` ATOM. Thus, reactivity on all the ring decreases , but to lesser extent at `m-C`. Therefore, `(-CF_(3))` group is `m`-director. Consequently, (o + p)//m` ratio is very low. |
|