1.

Why are (o + p) in ratious for the SE reaction (e.g. nitraction) of toluene and PhCF, 32.3 and 0.14, respectively ?

Answer»

Solution :In TOULENE, `(-CH_(3))` group is the activating group (due to three `H.C`. Sturctures). Also, it is `sigma-` and `p` directing so `(( o + p))/(m)` ratio is very high.
In PhCF_(3), (-CF_(3))` is the decavating group to `-1` effect of three `F` atoms on the `ALKYL C` ATOM. Thus, reactivity on all the ring decreases , but to lesser extent at `m-C`. Therefore, `(-CF_(3))` group is `m`-director. Consequently, (o + p)//m` ratio is very low.


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