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| 1. |
Why blue colour of copper suphate solution gets dischared when zinc rod is dipped inti ? Given E_(Cu^(2+//Cu))^(@)=0.34V "and" E_(Zn//Zn^(2+))^(@)=0.76 V |
| Answer» Solution :Since `E_(Zn,Zn^(2+))^(@)=-E_(Zn^(2+),Zn)^(@)=-0.76V` is lower than `E_(Cu^(2+),Cu)^(@)`therefore Zn will lose electrons and copper will accept them in other words the FOLLOWING reaction will occur `Zn+Cu^(2+)rarrZn^(2+)+Cu` since blue `Cu^(2+)` ions are consumed and colourless `Zn^(2+)` ions are PRODUCED during the above rections therefore colour of `CuSO_(4)` solution gets DISCHARGED when zinc ROD is dipped in it | |