InterviewSolution
Saved Bookmarks
InterviewSolution
| 1. |
Why following two reaction proceed differently? `Pb_(3)O_(4)+8HClrarr3PbCl_(2)+Cl_(2)+4H_(2)O` and `Pb_(3)O_(4)+4HNO_(3)rarr2Pb(NO_(3))_(2)+PbO_(2)+2H_(2)O`A. three numbers of `Pb^(2+)` ions get oxidised to `Pb^(4+)` stateB. one number `Pb^(4+)` ion gets reduced to `Pb^(2+)` and two numbers of `Pb^(2+)` ions remain unchanged in their oxidation stateC. one number `Pb^(2+)` ion gets oxidised to `Pb^(4+)` and two numbers of `Pb^(4+)` ions remain unchanged in their oxidation statesD. three numbers of `Pb^(4+)` ions get reduced to `Pb^(2+)` state. |
|
Answer» Correct Answer - B `Pb_(3)O_(4)`is a mixture of PbO and `PbO_(2)`. `Pn_(3)O_(4)-=2PnO*PnO_(2)+8HCl rarr 3PnCl_(2)+Cl_(2)+4H_(2)O` In the reaction one `Pn^(4+)` ion is reduced to `Pb^(2+)` and two `Pb^(2+)` ions remain unchanged. |
|