why in NaBH4 oxidation no of B is -3

1.	why in NaBH4 oxidation no of B is -3
Answer» Let the oxidation number of B in NaBH4 is xthen, oxidation number of Na+oxidation number of B+oxidation number of H=net charge on NaBH4=1+x+(-1)4=0=x-4+1=0x=+3

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