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Why is Bi(V) a stroger oxidant than Sb(V) ? Or of Bi (V) and Sb (V) which may be a stronger oxidising agent and why ?

Answer» Due to inert effect, +3 oxidation state of Bi is moer stable than its +5 oxidation state while +5 oxidation state of Sb is more stable than its +3 oxidation state. Therefore, Bi(V) can more easily accept a pair of electrons and get reduced to form more stable Bi(III) than Sb(V) can accept a pair of electrons. In other works, Bi(V) is a stronger oxidising agent than Sb(V).


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