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    				| 1. | Why is it necessary to test for the acid redicals first (with dilute) `H_(2)SO_(4)` and then with conc. `H_(2)SO_(4)`? | 
| Answer» There are some ions like, `SO_(3)^(2-),S^(2-),NO_(2)^(ɵ)`, and `CH_(3)COO^(ɵ)` which can react with dilute/conc. `H_(2)SO_(4)` whereas ions like `Cl^(ɵ),Br^(ɵ),I^(ɵ),NO_(3)^(ɵ)`, etc. react only with conc. `H_(2)SO_(4)`. Now if conc. `H_(2)SO_(4)` is used first then the anions of both the types will react. Hence it is desired to test acid radicals first with dilute `H_(2)SO_(4)` and then with conc. `H_(2)SO_(4)`. | |