1.

Why `KHF_(2)` exists but `KHCl_(2)` does not ?

Answer» Due to H-bonding in HF, we have
`H-F----H-F----H-F----`
This can dissociate to give `HF_(2)^(-)` ion and hence `KHF_(2)` exists but there is no H-bonding in H-Cl. So `Hcl_(2)^(-)`
ion does not exist and hence `KHCl_(2)` also does not exist


Discussion

No Comment Found

Related InterviewSolutions