1.

Will a precipitate of Mg(OH)2 be formed in a 0.002 M solution of Mg(NO3)2, if the pH of solution is adjusted to 9 ? Ksp of Mg(OH)2 = 8.9 × 10–12.

Answer»

pH = 9

∴ [H+ ] = 10–9

or [OH] = 10–5

Now if Mg(NO3)2 is present in a solution of [OH] = 10–5 M, then, 

Product of ionic conc. = [Mg+2] [OH ]2 = [0.002] [[10–5]2 

 = 2 × 10–13 lesser than Ksp of Mg(OH)2 i.e, 8.9 × 10–12 

∴ Mg(OH)2 will not precipitate.



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