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Will a precipitate of Mg(OH)2 be formed in a 0.002 M solution of Mg(NO3)2, if the pH of solution is adjusted to 9 ? Ksp of Mg(OH)2 = 8.9 × 10–12. |
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Answer» pH = 9 ∴ [H+ ] = 10–9 M or [OH– ] = 10–5 M Now if Mg(NO3)2 is present in a solution of [OH–] = 10–5 M, then, Product of ionic conc. = [Mg+2] [OH– ]2 = [0.002] [[10–5]2 = 2 × 10–13 lesser than Ksp of Mg(OH)2 i.e, 8.9 × 10–12 ∴ Mg(OH)2 will not precipitate. |
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