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Wires `1 and 2` carrying currents `i_(1) and i_(2)` respectively are inclined at an angle `theta ` to each other. What is the force on a small element `dl` of wire `2` at a distance of `r` from wire 1 ( as shown in figure) due to the magnetic field of wire 1`? A. `(mu_(0))/(2pir) i_(1) i_(2) dl tan theta`B. `(mu_(0))/(2pir) i_(1) i_(2) dl sin theta`C. `(mu_(0))/(2pir) i_(1) i_(2) dl cos theta`D. `(mu_(0))/(4pir) i_(1) i_(2) dl sin theta` |
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Answer» Correct Answer - C |
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