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With the data of the above problem, the strain energy per unit volume stored in the wires is,A. `4xx10^(2)J//m^(3)`B. `4 xx 10^(3)J//m^(3)`C. `4 J//m^(3)`D. `4xx10^(5)J//m^(3)` |
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Answer» Correct Answer - D `u=(W)/(v) =(0.4)/(AL)=(0.4)/(10^(-6) xx1)` `u=0.4xx10^(6)` `=4xx10^(5) J//m^(3)`. |
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