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With the help of first law of thermodynamics and H=U +PV prove delta heat =qp |
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Answer» halpy is defined by H = E + PV for a change in the states of system ΔH = Δ (E + pV) = ΔE + Δ (pV) = ΔE + pΔV + VΔp ....(i) 1st LAW of thermodynamics states that ΔE = Q + W = q - pΔV ....(ii) From equations (i) and (ii) ΔH = q - pΔV + pΔV + VΔp = q + VΔp When the pressure is constant, Δp = 0, and thus VΔp = 0, therefore ΔH = q (at constant pressure) or, ΔH = qP |
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